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=DBQ P13= Size and magnification

Question 1
magnfication = size of image / actual size of the specimen (a) Size of the image (Scalebar) 20 mm, Actual size 0.2 mm; Magnification 20 / 0.2 = X100 (b) Width of //Thiomargarita// in the image 26mm, magnification 100 x ;actual size= 26/100 = 0,26 mm

Question 2
(a) Magnification= length mitochondrion in the image (63 mm) / Actual size of the speciment (8 um 0.008 mm) = 63 / 0.008 = x 7875

(b) Scale bar 5um x 7875 = 39 375 um ( approx 40mm). (c) Width on the image 23mm / magnification 7875 = 0.0029 mm (2.9 um)

Question 3
a) 20 um x 2000 (magnfication) = 40, 000 um ( or 40 mm Scale bar). b) Cell lengths from image ( 16mm, 20mm, 16mm, 17mm, 17mm, 19 mm)= average cell length =17.5 mm on the image { depends on measurements} Actual size of specimen 17.7 mm/ 2000 = 0.0087mm or 8.7 um (this seems small to me!)

Question 4
(a) Hens egg is 16mm in diagram. Ostrich egg is 46 mm long in diagram. Real hen egg is about 50mm wide. Ostrich egg (50 x 46)/16 = 144 mm approx. (b) magnification = size image / actual size of the specimen Hens egg : Magnification 16 mm /50 mm x 0.32

=DBQ P15=

Question 2.
Trendlines a) Straight line suggests we are not sure where the points would be for intermediate data. b) Curve: suggest we know where all the points of intermediate data would occur. c) Line of best fit: suggest we know the overall relationship even if we are not sure of the intermediate values. The case is better made for option (c)

Question 3
Explain: The mass can be taken as a measure of the volume of the cell based on the assumption that the density of tissue does not vary a great deal from one small mammal to another. Therefore the ‘larger’ of the small mammals such as the mouse or the gerbil have proportionally less surface area for a given volume than mammals like the Etruscan shrew and the Pygmy shrew. The mouse and gerbil have smaller surface area: mass (volume) ratio than pygmy shrew or Etruscan shrew.

=DBQ P16= 1. 8 patients had benign tumours; 5 had malignant tumours